extreme f(x)=-4t^2+6t-1

解答

极值点

f (x) = - 4 t^{2} + 6 t - 1

极大值 (\frac{3}{4}, \frac{5}{4})

求解步骤

f^{'} (t) = - 8 t + 6

Find intervals:

递增

: - \infty < t < \frac{3}{4},

递减

: \frac{3}{4} < t < \infty

将

t = \frac{3}{4}

代入

- 4 t^{2} + 6 t - 1 : \frac{5}{4}

极大值 (\frac{3}{4}, \frac{5}{4})

d o main \frac{1}{12 - t}

r an g e \frac{1}{4} tan (\frac{1}{8} x) - 2

a sy m pt o t es f (x) = \frac{x - 2}{( x + 2 ) ( x - 2 )}

e x t re m e f (x) = x^{2} - 8 x + 20

d o main f (x) = \frac{4 x ^{2} - 1}{∣ 2 x + 1 ∣}