inflection f(x)=x^4-4x^3-2x^2

Lösung

wendepunkte

f (x) = x^{4} - 4 x^{3} - 2 x^{2}

(\frac{3 - 2 3}{3}, \frac{216 - 125 3}{9 3}), (\frac{3 + 2 3}{3}, \frac{- 125 3 - 216}{9 3})

Schritte zur Lösung

f^{''} (x) = 12 x^{2} - 24 x - 4

Intervalle finden:

Konkav steigend

: - \infty < x < - \frac{2}{3} + 1,

Konkav fallend

: - \frac{2}{3} + 1 < x < \frac{2}{3} + 1,

Konkav steigend

: \frac{2}{3} + 1 < x < \infty

Stecke

x = \frac{3 - 2 3}{3}

x^{4} - 4 x^{3} - 2 x^{2} : \frac{216 - 125 3}{9 3}

(\frac{3 - 2 3}{3}, \frac{216 - 125 3}{9 3})

Stecke

x = \frac{3 + 2 3}{3}

x^{4} - 4 x^{3} - 2 x^{2} : \frac{- 125 3 - 216}{9 3}

(\frac{3 + 2 3}{3}, \frac{- 125 3 - 216}{9 3})

(\frac{3 - 2 3}{3}, \frac{216 - 125 3}{9 3}), (\frac{3 + 2 3}{3}, \frac{- 125 3 - 216}{9 3})

p a r i t y f (x) = 3 x^{4} + 5 x^{2} + 1

d o main f (x) = \frac{x + 1}{x - 7}

in v erse f (x) = (x + 4)^{3} - 2

f (x) = 2 sin (x)

sy mm e t ry x y = 7