-f(x)=4x^2+2x-4

Lösung

- f (x) = 4 x^{2} + 2 x - 4

(h, k) = (- \frac{1}{4}, \frac{17}{4}), p = - \frac{1}{16}

Schritte zur Lösung

- y = 4 x^{2} + 2 x - 4

Rewrite

- y = 4 x^{2} + 2 x - 4

in the standard form

4 (- \frac{1}{16}) (y - \frac{17}{4}) = (x - (- \frac{1}{4}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{4}, \frac{17}{4}), p = - \frac{1}{16}

x + y^{2} = 1

3 x^{2} + y = 14

4 x^{2} - 5 y = 7

4 y^{2} - 5 x - 12 = 0

3 x^{2} + y = 5