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Beliebt Geometry >

pix^{(2)}+piy^{(2)}+8x-10piy-400=0

Lösung

π x^{(2)} + π y^{(2)} + 8 x - 10 π y - 400 = 0

Lösung

(a, b) = (- \frac{4}{π}, 5), r = \frac{400 π + 16 + 25 π ^{2}}{π}

Schritte zur Lösung

π x^{2} + π y^{2} + 8 x - 10 π y - 400 = 0

Rewrite

π x^{2} + π y^{2} + 8 x - 10 π y - 400 = 0

in the form of the standard circle equation

(x - (- \frac{4}{π}))^{2} + (y - 5)^{2} = (\frac{400 π + 16 + 25 π ^{2}}{π})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{4}{π}, 5), r = \frac{400 π + 16 + 25 π ^{2}}{π}

Graph

Beliebte Beispiele

(x+3)^2+(y-9)^2=21

(x + 3)^{2} + (y - 9)^{2} = 21

5x^2+5y^2+10x-y=10

5 x^{2} + 5 y^{2} + 10 x - y = 10

(x+3)^2+(y+5)^2=5

(x + 3)^{2} + (y + 5)^{2} = 5

(x+2)^2+(y+9)^2=70

(x + 2)^{2} + (y + 9)^{2} = 70

x^2+y^2-8x-6y=20

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