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Beliebt Geometry >

center x^2+y^2-2x-4y-4=0

Lösung

center

x^{2} + y^{2} - 2 x - 4 y - 4 = 0

Lösung

(1, 2)

Schritte zur Lösung

x^{2} + y^{2} - 2 x - 4 y - 4 = 0

Rewrite

x^{2} + y^{2} - 2 x - 4 y - 4 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - 2)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (1, 2), r = 3

And the center is:

(1, 2)

Graph

Beliebte Beispiele

center 2x^2+2y^2-8=0

ce n t er 2 x^{2} + 2 y^{2} - 8 = 0

center x^2+y^2+14x-12y+4=0

ce n t er x^{2} + y^{2} + 14 x - 12 y + 4 = 0

center x^2+y^2+4x+4y+7=0

ce n t er x^{2} + y^{2} + 4 x + 4 y + 7 = 0

center x^2+y^2-10x-16y+53=0

ce n t er x^{2} + y^{2} - 10 x - 16 y + 53 = 0

center (x+2)^2+(y+3)^2=9

ce n t er (x + 2)^{2} + (y + 3)^{2} = 9