kreisumfang 3x^2+3y^2+4y-7=0

Lösung

kreisumfang

3 x^{2} + 3 y^{2} + 4 y - 7 = 0

C = \frac{10 π}{3}

Schritte zur Lösung

C = 2 π r

Finde den Radius

Radius given

3 x^{2} + 3 y^{2} + 4 y - 7 = 0 : r = \frac{5}{3}

C = 2 π \frac{5}{3}

Fasse zusammen

C = \frac{10 π}{3}

c i rc u m f ere n ce x^{2} + y^{2} + 4 x + 12 y - 100 = 0

c i rc u m f ere n ce (x - 5)^{2} + (y - 2)^{2} = 25

c i rc u m f ere n ce X^{2} + 4 X + Y^{2} - 6 Y + 9 = 0

c i rc u m f ere n ce x^{2} + (y - 2)^{2} = 1

c i rc u m f ere n ce x^{2} + y^{2} + 4 x + 12 y - 104 = 0