2x^2+3y^2+10x+9y-19=0

Lösung

2 x^{2} + 3 y^{2} + 10 x + 9 y - 19 = 0

(h, k) = (- \frac{5}{2}, - \frac{3}{2}), a = \frac{3 17}{2 2}, b = \frac{51}{2}

Schritte zur Lösung

2 x^{2} + 3 y^{2} + 10 x + 9 y - 19 = 0

Rewrite

2 x^{2} + 3 y^{2} + 10 x + 9 y - 19 = 0

in the form of the standard ellipse equation

\frac{( x - ( - \frac{5}{2} ) ) ^{2}}{( \frac{3 17}{2 2} ) ^{2}} + \frac{( y - ( - \frac{3}{2} ) ) ^{2}}{( \frac{51}{2} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- \frac{5}{2}, - \frac{3}{2}), a = \frac{3 17}{2 2}, b = \frac{51}{2}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- \frac{5}{2}, - \frac{3}{2}), a = \frac{3 17}{2 2}, b = \frac{51}{2}

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