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Beliebt Geometry >

5x^2+y^2+4x-16=0

Lösung

5 x^{2} + y^{2} + 4 x - 16 = 0

Lösung

(h, k) = (- \frac{2}{5}, 0), a = \frac{2 21}{5}, b = \frac{2 21}{5}

Schritte zur Lösung

5 x^{2} + y^{2} + 4 x - 16 = 0

Rewrite

5 x^{2} + y^{2} + 4 x - 16 = 0

in the form of the standard ellipse equation

\frac{( x - ( - \frac{2}{5} ) ) ^{2}}{( \frac{2 21}{5} ) ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{2 21}{5} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- \frac{2}{5}, 0), a = \frac{2 21}{5}, b = \frac{2 21}{5}

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- \frac{2}{5}, 0), b = \frac{2 21}{5}, a = \frac{2 21}{5}

Graph

Beliebte Beispiele

x^{2} + \frac{y ^{2}}{2} = 1

((x+8)^2)/(16)+((y+1)^2)/(81)=1

\frac{( x + 8 ) ^{2}}{16} + \frac{( y + 1 ) ^{2}}{81} = 1

((x-12)^2)/(289)+((y-3)^2)/(64)=1

\frac{( x - 12 ) ^{2}}{289} + \frac{( y - 3 ) ^{2}}{64} = 1

3x^2+6y^2-4x+6y-3=0

3 x^{2} + 6 y^{2} - 4 x + 6 y - 3 = 0

((x+1)^2)/4+((y-3)^2)/9 =1

\frac{( x + 1 ) ^{2}}{4} + \frac{( y - 3 ) ^{2}}{9} = 1