16x^2+36y^2=49

Lösung

16 x^{2} + 36 y^{2} = 49

(h, k) = (0, 0), a = \frac{7}{4}, b = \frac{7}{6}

Schritte zur Lösung

16 x^{2} + 36 y^{2} = 49

Rewrite

16 x^{2} + 36 y^{2} = 49

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( \frac{7}{4} ) ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{7}{6} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = \frac{7}{4}, b = \frac{7}{6}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = \frac{7}{4}, b = \frac{7}{6}

\frac{( x + 1.23 ) ^{2}}{1.5 9 ^{2}} + \frac{y ^{2}}{1.0 1 ^{2}} = 1

\frac{x ^{2}}{12} + \frac{y ^{2}}{9} = 1

5 x^{2} + 6 y^{2} - 30 x - 24 y + 39 = 0

\frac{( x ^{2} )}{( 16 )} + \frac{( y ^{2} )}{( 12 )} = 1

\frac{( x - 3 ) ^{2}}{16} + \frac{( y - 7 ) ^{2}}{64} = 1