x^2+5y^2= 1/5

Lösung

x^{2} + 5 y^{2} = \frac{1}{5}

(h, k) = (0, 0), a = \frac{1}{5}, b = \frac{1}{5}

Schritte zur Lösung

x^{2} + 5 y^{2} = \frac{1}{5}

Rewrite

x^{2} + 5 y^{2} = \frac{1}{5}

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( \frac{1}{5} ) ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{1}{5} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = \frac{1}{5}, b = \frac{1}{5}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = \frac{1}{5}, b = \frac{1}{5}

3 x^{2} + 12 y^{2} + 18 x - 24 y - 69 = 0

3 y^{2} + 5 x^{2} = 20

\frac{( x - 4 ) ^{2}}{36} + \frac{( y - 2 ) ^{2}}{20} = 1

\frac{x ^{2}}{16} + \frac{y ^{2}}{8} = 1

4 x^{2} + 9 y^{2} + 24 x = 0