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Beliebt Geometry >

center 3x^2+4y^2+12x-8y+9=0

Lösung

center

3 x^{2} + 4 y^{2} + 12 x - 8 y + 9 = 0

Lösung

(- 2, 1)

Schritte zur Lösung

3 x^{2} + 4 y^{2} + 12 x - 8 y + 9 = 0

Rewrite

3 x^{2} + 4 y^{2} + 12 x - 8 y + 9 = 0

in the form of the standard ellipse equation

\frac{( x - ( - 2 ) ) ^{2}}{( \frac{7}{3} ) ^{2}} + \frac{( y - 1 ) ^{2}}{( \frac{7}{2} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 2, 1), a = \frac{7}{3}, b = \frac{7}{2}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 2, 1), a = \frac{7}{3}, b = \frac{7}{2}

And the center is:

(- 2, 1)

Graph

Beliebte Beispiele

center x^2+y^2<= y

ce n t er x^{2} + y^{2} \leq y

center 4x^2+25y^2-32x+200y+364=0

ce n t er 4 x^{2} + 25 y^{2} - 32 x + 200 y + 364 = 0

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ce n t er x^{2} + 10 x + 9 y^{2} + 16 = 0