2400^2x^2=460^2(x^2+z^2+36)

解

240 0^{2} x^{2} = 46 0^{2} (x^{2} + z^{2} + 36)

(h, k) = (0, 0), a = \frac{138}{13871}, b = 6

解答ステップ

240 0^{2} x^{2} = 46 0^{2} (x^{2} + z^{2} + 36)

240 0^{2} x^{2} - 46 0^{2} (x^{2} + z^{2} + 36) = 0

を標準的な双曲線のequationで書き換える

\frac{( x - 0 ) ^{2}}{( \frac{138}{13871} ) ^{2}} - \frac{( z - 0 ) ^{2}}{6 ^{2}} = 1

ゆえに双曲線の特性は:

(h, k) = (0, 0), a = \frac{138}{13871}, b = 6