(x+2)^2=y+1

Lösung

(x + 2)^{2} = y + 1

(h, k) = (- 2, - 1), p = \frac{1}{4}

Schritte zur Lösung

(x + 2)^{2} = y + 1

Rewrite

(x + 2)^{2} = y + 1

in the standard form:

4 \cdot \frac{1}{4} (y - (- 1)) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, - 1), p = \frac{1}{4}

y^{2} + 12 y - 4 x + 48 = 0

x^{2} - y = 6

y^{2} = 4 (x + 1)

(y - 7)^{2} = - 12 (x - 1)

100 y = 23 x^{2}