(y+4)^2=4(x+1)

Lösung

(y + 4)^{2} = 4 (x + 1)

(h, k) = (- 1, - 4), p = 1

Schritte zur Lösung

(y + 4)^{2} = 4 (x + 1)

Rewrite

(y + 4)^{2} = 4 (x + 1)

in the standard form:

4 \cdot 1 \cdot (x - (- 1)) = (y - (- 4))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - 4), p = 1

(x + 1)^{2} = - 8 (y - 4)

x = - 7 y^{2}

(y + 1)^{2} + 2 x = 4

(x - 2)^{2} = 4 (y - 3)

(y + 2)^{2} = - 8 (x - 1)