3x^2=6+2y

Lösung

3 x^{2} = 6 + 2 y

(h, k) = (0, - 3), p = \frac{1}{6}

Schritte zur Lösung

3 x^{2} = 6 + 2 y

Rewrite

3 x^{2} = 6 + 2 y

in the standard form:

4 \cdot \frac{1}{6} (y - (- 3)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 3), p = \frac{1}{6}

x = y^{2} - 5 y

x = y^{2} - 16

- x^{2} + y \geq 1

y^{2} + 12 x - 10 y + 1 = 0

2 (- y + 1) = (\frac{1}{2} (x - 1))^{2}