r^2h= v/pi

Lösung

r^{2} h = \frac{v}{π}

(h, k) = (0, 0), p = \frac{1}{4 πh}

Schritte zur Lösung

r^{2} h = \frac{v}{π}

Rewrite

r^{2} h = \frac{v}{π}

in the standard form:

4 \cdot \frac{1}{4 πh} (v - 0) = (r - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{4 πh}

3 (x - 2)^{2} - 5 y = 6

X^{2} - 10 X - 32 Y + 57 = 0

(x - 3)^{2} = - 14 (y - 2)

y = - 2 x^{2} - 20 x - 45

4 x^{2} + y = 12