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Beliebt Geometry >

foki y=2x^2+16x+29

Lösung

foki

y = 2 x^{2} + 16 x + 29

Lösung

(- 4, - \frac{23}{8})

Schritte zur Lösung

Rewrite

y = 2 x^{2} + 16 x + 29

in the standard form

4 \cdot \frac{1}{8} (y - (- 3)) = (x - (- 4))^{2}

(h, k) = (- 4, - 3), p = \frac{1}{8}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 4, - 3)

along the y-axis

(- 4, - 3 + p)

= (- 4, - 3 + \frac{1}{8})

Fasse zusammen

(- 4, - \frac{23}{8})

Graph

Beliebte Beispiele

f oc i y = (x + 5)^{2}

f oc i x^{2} + 2 x + 6

foki y=2x^2-4x+15

f oc i y = 2 x^{2} - 4 x + 15

f oc i x^{2} + 2 x - 2

f oc i 2 y^{2} = 3 x