y^2=20x

Lösung

y^{2} = 20 x

(h, k) = (0, 0), p = 5

Schritte zur Lösung

y^{2} = 20 x

Rewrite

y^{2} = 20 x

in the standard form:

4 \cdot 5 (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = 5

d i rec t r i x x^{2} + 8 y = 0

v er t i ces \frac{x ^{2}}{16} - \frac{y ^{2}}{36} = 1

v er t i ces (x + 2)^{2} + \frac{( y + 4 ) ^{2}}{\frac{1}{4}} = 1

f oc i \frac{x ^{2}}{25} + \frac{y ^{2}}{16} = 1

f oc i \frac{x ^{2}}{16} + \frac{y ^{2}}{7} = 1