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受欢迎的初等代数 >

(25+3(5× 3))\div ((6+8)\div (6+3))

解答

(25 + 3 (5 \times 3)) \div ((6 + 8) \div (6 + 3))

解答

45

求解步骤

(25 + 3 (5 \times 3)) \div ((6 + 8) \div (6 + 3))

遵循 PEMDAS 运算顺序

计算括号内的值

(25 + 3 (5 \times 3)) : 70

25 + 3 (5 \times 3)

计算括号内的值

(5 \times 3) : 15

5 \times 3

5 \times 3 = 15

= 15

= 25 + 3 \cdot 15

乘除（左右）

3 \cdot 15 : 45

3 \cdot 15

3 \cdot 15 = 45

= 45

= 25 + 45

加减（左右）

25 + 45 : 70

25 + 45

25 + 45 = 70

= 70

= 70

= 70 \div ((6 + 8) \div (6 + 3))

计算括号内的值

((6 + 8) \div (6 + 3)) : \frac{14}{9}

(6 + 8) \div (6 + 3)

计算括号内的值

(6 + 8) : 14

6 + 8

6 + 8 = 14

= 14

= 14 \div (6 + 3)

计算括号内的值

(6 + 3) : 9

6 + 3

6 + 3 = 9

= 9

= 14 \div 9

乘除（左右）

14 \div 9 : \frac{14}{9}

14 \div 9

14 \div 9 = \frac{14}{9}

= \frac{14}{9}

= \frac{14}{9}

= 70 \div \frac{14}{9}

乘除（左右）

70 \div \frac{14}{9} : 45

70 \div \frac{14}{9}

将项转换为分式:

70 = \frac{70}{1}

= \frac{70}{1} \div \frac{14}{9}

使用分式法则:

\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}

= \frac{70}{1} \cdot \frac{9}{14}

交叉约去公约数:

14

= \frac{5}{1} \cdot \frac{9}{1}

分式相乘:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{5 \cdot 9}{1 \cdot 1}

数字相乘:

5 \cdot 9 = 45

= \frac{45}{1 \cdot 1}

数字相乘:

1 \cdot 1 = 1

= \frac{45}{1}

使用法则

\frac{a}{1} = a

= 45

= 45

流行的例子

(81\div 3*5-200\div 50+4)*2

(81 \div 3 \cdot 5 - 200 \div 50 + 4) \cdot 2

3 \frac{1}{2} + 2 - \frac{1}{3}

3× (-5)× (-1)

3 \times (- 5) \times (- 1)

8 - 6 - (6 \cdot 5) + 6^{2}

(-15)*2-(-16)\div (-8)

(- 15) \cdot 2 - (- 16) \div (- 8)