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受欢迎的初等代数 >

216/41+525/41

解答

2 \cdot \frac{16}{41} + 5 \cdot \frac{25}{41}

解答

3 \frac{34}{41}

+1

十进制

3.82926 \dots

求解步骤

2 \cdot \frac{16}{41} + 5 \cdot \frac{25}{41}

遵循 PEMDAS 运算顺序

乘除（左右）

2 \cdot \frac{16}{41} : \frac{32}{41}

2 \cdot \frac{16}{41}

将项转换为分式:

2 = \frac{2}{1}

= \frac{2}{1} \cdot \frac{16}{41}

使用分式法则:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{2 \cdot 16}{1 \cdot 41}

数字相乘:

2 \cdot 16 = 32

= \frac{32}{1 \cdot 41}

数字相乘:

1 \cdot 41 = 41

= \frac{32}{41}

= \frac{32}{41} + 5 \cdot \frac{25}{41}

乘除（左右）

5 \cdot \frac{25}{41} : \frac{125}{41}

5 \cdot \frac{25}{41}

将项转换为分式:

5 = \frac{5}{1}

= \frac{5}{1} \cdot \frac{25}{41}

使用分式法则:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{5 \cdot 25}{1 \cdot 41}

数字相乘:

5 \cdot 25 = 125

= \frac{125}{1 \cdot 41}

数字相乘:

1 \cdot 41 = 41

= \frac{125}{41}

= \frac{32}{41} + \frac{125}{41}

加减（左右）

\frac{32}{41} + \frac{125}{41} : \frac{157}{41}

\frac{32}{41} + \frac{125}{41}

\frac{32}{41} + \frac{125}{41} = \frac{157}{41}

\frac{32}{41} + \frac{125}{41}

使用法则

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{32 + 125}{41}

数字相加:

32 + 125 = 157

= \frac{157}{41}

= \frac{157}{41}

= \frac{157}{41}

将假分式转换为带分数:

\frac{157}{41} = 3 \frac{34}{41}

\frac{157}{41} = 3

余数

34

\frac{157}{41}

将问题写为长除法形式

41 \overline{∣ 157}

将

157

除以

41

以得到

3

将

157

除以

41

以得到

3

3 41 \overline{∣ 157}

将商数

(3)

乘以除数

41

3 41 \overline{∣ 157} \underline{123}

从

157

减去

123

3 41 \overline{∣ 157} \underline{123} 34

3 41 \overline{∣ 157} \underline{123} 34

长除

\frac{157}{41}

的解是

3

，余数是

34

3 余数 34

转换为带分数: 商

\frac{余数}{除数}

\frac{157}{41} = 3 \frac{34}{41}

= 3 \frac{34}{41}

= 3 \frac{34}{41}

流行的例子

4 - 6 - 9 - 7 - 2 + 8

(8-3/5)\div 3 1/2

(8 - \frac{3}{5}) \div 3 \frac{1}{2}

1^{2} + 8^{2}

8 (2)^{2} - 11

1 \cdot 1 0^{0}