cos(θ)= 12/13

Lösung

cos (θ) = \frac{12}{13}

θ = 0.39479 \dots + 2 πn, θ = 2 π - 0.39479 \dots + 2 πn

Grad

θ = 22.61986 \dots^{\circ} + 36 0^{\circ} n, θ = 337.38013 \dots^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

cos (θ) = \frac{12}{13}

Wende die Eigenschaften der Trigonometrie an

cos (θ) = \frac{12}{13}

Allgemeine Lösung für

cos (θ) = \frac{12}{13}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{12}{13}) + 2 πn, θ = 2 π - arccos (\frac{12}{13}) + 2 πn

θ = arccos (\frac{12}{13}) + 2 πn, θ = 2 π - arccos (\frac{12}{13}) + 2 πn

Zeige Lösungen in Dezimalform

θ = 0.39479 \dots + 2 πn, θ = 2 π - 0.39479 \dots + 2 πn

sin (2 θ) = cos (2 θ)

cosh (z) = 0

cos (x) = \frac{2}{π}

tan^{2} (x) + 3 tan (x) + 1 = 0

csc (2 x) = 2, 0 \leq x < 2 π