cos(θ)=(sqrt(11))/6

Lösung

cos (θ) = \frac{11}{6}

θ = 0.98511 \dots + 2 πn, θ = 2 π - 0.98511 \dots + 2 πn

Grad

θ = 56.44269 \dots^{\circ} + 36 0^{\circ} n, θ = 303.55730 \dots^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

cos (θ) = \frac{11}{6}

Wende die Eigenschaften der Trigonometrie an

cos (θ) = \frac{11}{6}

Allgemeine Lösung für

cos (θ) = \frac{11}{6}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{11}{6}) + 2 πn, θ = 2 π - arccos (\frac{11}{6}) + 2 πn

θ = arccos (\frac{11}{6}) + 2 πn, θ = 2 π - arccos (\frac{11}{6}) + 2 πn

Zeige Lösungen in Dezimalform

θ = 0.98511 \dots + 2 πn, θ = 2 π - 0.98511 \dots + 2 πn

2 cot (θ) + 1 = 0

tan (4 x) + 1 = 0

tan^{2} (x) - 3 = 0, 0 \leq x \leq 2 π

4 sin (θ) + 22 = 0

5 cos (θ) = - 53 sin (- θ)