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人気のある三角関数 >

6sin^2(x)=5

解

6 sin^{2} (x) = 5

解

x = 1.15026 \dots + 2 πn, x = π - 1.15026 \dots + 2 πn, x = - 1.15026 \dots + 2 πn, x = π + 1.15026 \dots + 2 πn

+1

度

x = 65.90515 \dots^{\circ} + 36 0^{\circ} n, x = 114.09484 \dots^{\circ} + 36 0^{\circ} n, x = - 65.90515 \dots^{\circ} + 36 0^{\circ} n, x = 245.90515 \dots^{\circ} + 36 0^{\circ} n

解答ステップ

6 sin^{2} (x) = 5

置換で解く

6 sin^{2} (x) = 5

仮定:

sin (x) = u

6 u^{2} = 5

6 u^{2} = 5 : u = \frac{5}{6}, u = - \frac{5}{6}

6 u^{2} = 5

以下で両辺を割る

6

6 u^{2} = 5

以下で両辺を割る

6

\frac{6 u ^{2}}{6} = \frac{5}{6}

簡素化

u^{2} = \frac{5}{6}

u^{2} = \frac{5}{6}

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

u = \frac{5}{6}, u = - \frac{5}{6}

代用を戻す

u = sin (x)

sin (x) = \frac{5}{6}, sin (x) = - \frac{5}{6}

sin (x) = \frac{5}{6}, sin (x) = - \frac{5}{6}

sin (x) = \frac{5}{6} : x = arcsin (\frac{5}{6}) + 2 πn, x = π - arcsin (\frac{5}{6}) + 2 πn

sin (x) = \frac{5}{6}

三角関数の逆数プロパティを適用する

sin (x) = \frac{5}{6}

以下の一般解

sin (x) = \frac{5}{6}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

x = arcsin (\frac{5}{6}) + 2 πn, x = π - arcsin (\frac{5}{6}) + 2 πn

x = arcsin (\frac{5}{6}) + 2 πn, x = π - arcsin (\frac{5}{6}) + 2 πn

sin (x) = - \frac{5}{6} : x = arcsin (- \frac{5}{6}) + 2 πn, x = π + arcsin (\frac{5}{6}) + 2 πn

sin (x) = - \frac{5}{6}

三角関数の逆数プロパティを適用する

sin (x) = - \frac{5}{6}

以下の一般解

sin (x) = - \frac{5}{6}

sin (x) = - a \Rightarrow x = arcsin (- a) + 2 πn, x = π + arcsin (a) + 2 πn

x = arcsin (- \frac{5}{6}) + 2 πn, x = π + arcsin (\frac{5}{6}) + 2 πn

x = arcsin (- \frac{5}{6}) + 2 πn, x = π + arcsin (\frac{5}{6}) + 2 πn

すべての解を組み合わせる

x = arcsin (\frac{5}{6}) + 2 πn, x = π - arcsin (\frac{5}{6}) + 2 πn, x = arcsin (- \frac{5}{6}) + 2 πn, x = π + arcsin (\frac{5}{6}) + 2 πn

10進法形式で解を証明する

x = 1.15026 \dots + 2 πn, x = π - 1.15026 \dots + 2 πn, x = - 1.15026 \dots + 2 πn, x = π + 1.15026 \dots + 2 πn

グラフ

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