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受欢迎的三角函数 >

cos(2x-a)=sin(3x)

解答

cos (2 x - a) = sin (3 x)

解答

x = \frac{π + 2 a + 4 πn}{10}, x = π - \frac{π}{2} - a + 2 πn

求解步骤

cos (2 x - a) = sin (3 x)

使用三角恒等式改写

cos (2 x - a) = sin (3 x)

利用以下特性:

cos (x) = sin (\frac{π}{2} - x)

cos (2 x - a) = sin (\frac{π}{2} - (2 x - a))

cos (2 x - a) = sin (\frac{π}{2} - (2 x - a))

使用反三角函数性质

cos (2 x - a) = sin (\frac{π}{2} - (2 x - a))

sin (x) = sin (y) \Rightarrow x = y + 2 π n, x = π - y + 2 π n

3 x = \frac{π}{2} - (2 x - a) + 2 πn, 3 x = π - (\frac{π}{2} - (2 x - a)) + 2 πn

3 x = \frac{π}{2} - (2 x - a) + 2 πn, 3 x = π - (\frac{π}{2} - (2 x - a)) + 2 πn

3 x = \frac{π}{2} - (2 x - a) + 2 πn : x = \frac{π + 2 a + 4 πn}{10}

3 x = \frac{π}{2} - (2 x - a) + 2 πn

展开

\frac{π}{2} - (2 x - a) + 2 πn : \frac{π}{2} - 2 x + a + 2 πn

\frac{π}{2} - (2 x - a) + 2 πn

- (2 x - a) : - 2 x + a

- (2 x - a)

打开括号

= - (2 x) - (- a)

使用加减运算法则

- (- a) = a, - (a) = - a

= - 2 x + a

= \frac{π}{2} - 2 x + a + 2 πn

3 x = \frac{π}{2} - 2 x + a + 2 πn

将

2 x

para o lado esquerdo

3 x = \frac{π}{2} - 2 x + a + 2 πn

两边加上

2 x

3 x + 2 x = \frac{π}{2} - 2 x + a + 2 πn + 2 x

化简

5 x = \frac{π}{2} + a + 2 πn

5 x = \frac{π}{2} + a + 2 πn

两边除以

5

5 x = \frac{π}{2} + a + 2 πn

两边除以

5

\frac{5 x}{5} = \frac{\frac{π}{2}}{5} + \frac{a}{5} + \frac{2 πn}{5}

化简

\frac{5 x}{5} = \frac{\frac{π}{2}}{5} + \frac{a}{5} + \frac{2 πn}{5}

化简

\frac{5 x}{5} : x

\frac{5 x}{5}

数字相除:

\frac{5}{5} = 1

= x

化简

\frac{\frac{π}{2}}{5} + \frac{a}{5} + \frac{2 πn}{5} : \frac{π + 2 a + 4 πn}{10}

\frac{\frac{π}{2}}{5} + \frac{a}{5} + \frac{2 πn}{5}

使用法则

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{\frac{π}{2} + a + 2 πn}{5}

化简

\frac{π}{2} + a + 2 πn : \frac{π + 2 a + 4 πn}{2}

\frac{π}{2} + a + 2 πn

将项转换为分式:

a = \frac{a 2}{2}, 2 πn = \frac{2 πn 2}{2}

= \frac{π}{2} + \frac{a \cdot 2}{2} + \frac{2 πn \cdot 2}{2}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{π + a \cdot 2 + 2 πn \cdot 2}{2}

数字相乘:

2 \cdot 2 = 4

= \frac{π + 2 a + 4 πn}{2}

= \frac{\frac{π + 2 a + 4 πn}{2}}{5}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π + a \cdot 2 + 4 πn}{2 \cdot 5}

数字相乘:

2 \cdot 5 = 10

= \frac{π + 2 a + 4 πn}{10}

x = \frac{π + 2 a + 4 πn}{10}

x = \frac{π + 2 a + 4 πn}{10}

x = \frac{π + 2 a + 4 πn}{10}

3 x = π - (\frac{π}{2} - (2 x - a)) + 2 πn : x = π - \frac{π}{2} - a + 2 πn

3 x = π - (\frac{π}{2} - (2 x - a)) + 2 πn

展开

π - (\frac{π}{2} - (2 x - a)) + 2 πn : π - \frac{π}{2} + 2 x - a + 2 πn

π - (\frac{π}{2} - (2 x - a)) + 2 πn

- (2 x - a) : - 2 x + a

- (2 x - a)

打开括号

= - (2 x) - (- a)

使用加减运算法则

- (- a) = a, - (a) = - a

= - 2 x + a

= π - (- 2 x + a + \frac{π}{2}) + 2 πn

- (\frac{π}{2} - 2 x + a) : - \frac{π}{2} + 2 x - a

- (\frac{π}{2} - 2 x + a)

打开括号

= - (\frac{π}{2}) - (- 2 x) - (a)

使用加减运算法则

- (- a) = a, - (a) = - a

= - \frac{π}{2} + 2 x - a

= π - \frac{π}{2} + 2 x - a + 2 πn

3 x = π - \frac{π}{2} + 2 x - a + 2 πn

将

2 x

para o lado esquerdo

3 x = π - \frac{π}{2} + 2 x - a + 2 πn

两边减去

2 x

3 x - 2 x = π - \frac{π}{2} + 2 x - a + 2 πn - 2 x

化简

x = π - \frac{π}{2} - a + 2 πn

x = π - \frac{π}{2} - a + 2 πn

x = \frac{π + 2 a + 4 πn}{10}, x = π - \frac{π}{2} - a + 2 πn

x = \frac{π + 2 a + 4 πn}{10}, x = π - \frac{π}{2} - a + 2 πn

作图

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