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人気のある三角関数 >

4tan(x)+2sin(x)cos(x)=0

解

4 tan (x) + 2 sin (x) cos (x) = 0

解

x = 2 πn, x = π + 2 πn

+1

度

x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n

解答ステップ

4 tan (x) + 2 sin (x) cos (x) = 0

サイン, コサインで表わす

4 tan (x) + 2 cos (x) sin (x)

基本的な三角関数の公式を使用する:

tan (x) = \frac{sin ( x )}{cos ( x )}

= 4 \cdot \frac{sin ( x )}{cos ( x )} + 2 cos (x) sin (x)

簡素化

4 \cdot \frac{sin ( x )}{cos ( x )} + 2 cos (x) sin (x) : \frac{4 sin ( x ) + 2 cos ^{2} ( x ) sin ( x )}{cos ( x )}

4 \cdot \frac{sin ( x )}{cos ( x )} + 2 cos (x) sin (x)

乗じる

4 \cdot \frac{sin ( x )}{cos ( x )} : \frac{4 sin ( x )}{cos ( x )}

4 \cdot \frac{sin ( x )}{cos ( x )}

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{sin ( x ) \cdot 4}{cos ( x )}

= \frac{4 sin ( x )}{cos ( x )} + 2 cos (x) sin (x)

元を分数に変換する:

2 cos (x) sin (x) = \frac{2 cos ( x ) sin ( x ) cos ( x )}{cos ( x )}

= \frac{sin ( x ) \cdot 4}{cos ( x )} + \frac{2 cos ( x ) sin ( x ) cos ( x )}{cos ( x )}

分母が等しいので, 分数を組み合わせる:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{sin ( x ) \cdot 4 + 2 cos ( x ) sin ( x ) cos ( x )}{cos ( x )}

sin (x) \cdot 4 + 2 cos (x) sin (x) cos (x) = 4 sin (x) + 2 cos^{2} (x) sin (x)

sin (x) \cdot 4 + 2 cos (x) sin (x) cos (x)

2 cos (x) sin (x) cos (x) = 2 cos^{2} (x) sin (x)

2 cos (x) sin (x) cos (x)

指数の規則を適用する:

a^{b} \cdot a^{c} = a^{b + c}

cos (x) cos (x) = cos^{1 + 1} (x)

= 2 sin (x) cos^{1 + 1} (x)

数を足す:

1 + 1 = 2

= 2 sin (x) cos^{2} (x)

= 4 sin (x) + 2 cos^{2} (x) sin (x)

= \frac{4 sin ( x ) + 2 cos ^{2} ( x ) sin ( x )}{cos ( x )}

= \frac{4 sin ( x ) + 2 cos ^{2} ( x ) sin ( x )}{cos ( x )}

\frac{4 sin ( x ) + 2 cos ^{2} ( x ) sin ( x )}{cos ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

4 sin (x) + 2 cos^{2} (x) sin (x) = 0

因数

4 sin (x) + 2 cos^{2} (x) sin (x) : 2 sin (x) (cos^{2} (x) + 2)

4 sin (x) + 2 cos^{2} (x) sin (x)

4

を書き換え

2 \cdot 2

= 2 \cdot 2 sin (x) + 2 sin (x) cos^{2} (x)

共通項をくくり出す

2 sin (x)

= 2 sin (x) (2 + cos^{2} (x))

2 sin (x) (cos^{2} (x) + 2) = 0

各部分を別個に解く

sin (x) = 0 or cos^{2} (x) + 2 = 0

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = 0

以下の一般解

sin (x) = 0

sin (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

解く

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

cos^{2} (x) + 2 = 0 :

解なし

cos^{2} (x) + 2 = 0

置換で解く

cos^{2} (x) + 2 = 0

仮定:

cos (x) = u

u^{2} + 2 = 0

u^{2} + 2 = 0 : u = 2 i, u = - 2 i

u^{2} + 2 = 0

2

を右側に移動します

u^{2} + 2 = 0

両辺から

2

を引く

u^{2} + 2 - 2 = 0 - 2

簡素化

u^{2} = - 2

u^{2} = - 2

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

u = - 2, u = - - 2

簡素化

- 2 : 2 i

- 2

累乗根の規則を適用する:

- a = - 1 a

- 2 = - 1 2

= - 1 2

虚数の規則を適用する:

- 1 = i

= 2 i

簡素化

- - 2 : - 2 i

- - 2

簡素化

- 2 : 2 i

- 2

累乗根の規則を適用する:

- a = - 1 a

- 2 = - 1 2

= - 1 2

虚数の規則を適用する:

- 1 = i

= 2 i

= - 2 i

u = 2 i, u = - 2 i

代用を戻す

u = cos (x)

cos (x) = 2 i, cos (x) = - 2 i

cos (x) = 2 i, cos (x) = - 2 i

cos (x) = 2 i :

解なし

cos (x) = 2 i

解なし

cos (x) = - 2 i :

解なし

cos (x) = - 2 i

解なし

すべての解を組み合わせる

解なし

すべての解を組み合わせる

x = 2 πn, x = π + 2 πn

グラフ

人気の例

3sin(x)+6cos(x)=4

3 sin (x) + 6 cos (x) = 4

3 tan (2 x + 1) = 2

tan(2x)-2=3tan(x)

tan (2 x) - 2 = 3 tan (x)

sin (x - \frac{π}{6}) = 0

arccot(x-2)=arccot(x-1)+arccot(x)

arccot (x - 2) = arccot (x - 1) + arccot (x)