zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的三角函数 >

cos(x+1/6 pi)cos(x-1/6 pi)=cos(2x)

解答

cos (x + \frac{1}{6} π) cos (x - \frac{1}{6} π) = cos (2 x)

解答

x = \frac{5 π}{6} + πn, x = \frac{π}{6} + πn

+1

度数

x = 15 0^{\circ} + 18 0^{\circ} n, x = 3 0^{\circ} + 18 0^{\circ} n

求解步骤

cos (x + \frac{1}{6} π) cos (x - \frac{1}{6} π) = cos (2 x)

使用三角恒等式改写

cos (x + \frac{1}{6} π) cos (x - \frac{1}{6} π) = cos (2 x)

使用三角恒等式改写

cos (x + \frac{1}{6} π)

使用角和恒等式:

cos (s + t) = cos (s) cos (t) - sin (s) sin (t)

= cos (x) cos (\frac{1}{6} π) - sin (x) sin (\frac{1}{6} π)

化简

cos (x) cos (\frac{1}{6} π) - sin (x) sin (\frac{1}{6} π) : \frac{3}{2} cos (x) - \frac{1}{2} sin (x)

cos (x) cos (\frac{1}{6} π) - sin (x) sin (\frac{1}{6} π)

cos (x) cos (\frac{1}{6} π) = \frac{3}{2} cos (x)

cos (x) cos (\frac{1}{6} π)

乘

\frac{1}{6} π : \frac{π}{6}

\frac{1}{6} π

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 π}{6}

乘以:

1 π = π

= \frac{π}{6}

= cos (\frac{π}{6}) cos (x)

化简

cos (\frac{π}{6}) : \frac{3}{2}

cos (\frac{π}{6})

使用以下普通恒等式:

cos (\frac{π}{6}) = \frac{3}{2}

cos (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{3}{2}

= \frac{3}{2} cos (x)

sin (x) sin (\frac{1}{6} π) = \frac{1}{2} sin (x)

sin (x) sin (\frac{1}{6} π)

乘

\frac{1}{6} π : \frac{π}{6}

\frac{1}{6} π

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 π}{6}

乘以:

1 π = π

= \frac{π}{6}

= sin (\frac{π}{6}) sin (x)

化简

sin (\frac{π}{6}) : \frac{1}{2}

sin (\frac{π}{6})

使用以下普通恒等式:

sin (\frac{π}{6}) = \frac{1}{2}

sin (x)

周期表（周期为

2 πn

"）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{1}{2}

= \frac{1}{2} sin (x)

= \frac{3}{2} cos (x) - \frac{1}{2} sin (x)

= \frac{3}{2} cos (x) - \frac{1}{2} sin (x)

使用角差恒等式:

cos (s - t) = cos (s) cos (t) + sin (s) sin (t)

= cos (x) cos (\frac{1}{6} π) + sin (x) sin (\frac{1}{6} π)

化简

cos (x) cos (\frac{1}{6} π) + sin (x) sin (\frac{1}{6} π) : \frac{3}{2} cos (x) + \frac{1}{2} sin (x)

cos (x) cos (\frac{1}{6} π) + sin (x) sin (\frac{1}{6} π)

cos (x) cos (\frac{1}{6} π) = \frac{3}{2} cos (x)

cos (x) cos (\frac{1}{6} π)

乘

\frac{1}{6} π : \frac{π}{6}

\frac{1}{6} π

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 π}{6}

乘以:

1 π = π

= \frac{π}{6}

= cos (\frac{π}{6}) cos (x)

化简

cos (\frac{π}{6}) : \frac{3}{2}

cos (\frac{π}{6})

使用以下普通恒等式:

cos (\frac{π}{6}) = \frac{3}{2}

cos (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{3}{2}

= \frac{3}{2} cos (x)

sin (x) sin (\frac{1}{6} π) = \frac{1}{2} sin (x)

sin (x) sin (\frac{1}{6} π)

乘

\frac{1}{6} π : \frac{π}{6}

\frac{1}{6} π

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 π}{6}

乘以:

1 π = π

= \frac{π}{6}

= sin (\frac{π}{6}) sin (x)

化简

sin (\frac{π}{6}) : \frac{1}{2}

sin (\frac{π}{6})

使用以下普通恒等式:

sin (\frac{π}{6}) = \frac{1}{2}

sin (x)

周期表（周期为

2 πn

"）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{1}{2}

= \frac{1}{2} sin (x)

= \frac{3}{2} cos (x) + \frac{1}{2} sin (x)

= \frac{3}{2} cos (x) + \frac{1}{2} sin (x)

(\frac{3}{2} cos (x) - \frac{1}{2} sin (x)) (\frac{3}{2} cos (x) + \frac{1}{2} sin (x)) = cos (2 x)

(\frac{3}{2} cos (x) - \frac{1}{2} sin (x)) (\frac{3}{2} cos (x) + \frac{1}{2} sin (x)) = cos (2 x)

两边减去

cos (2 x)

(\frac{3}{2} cos (x) - \frac{1}{2} sin (x)) (\frac{3}{2} cos (x) + \frac{1}{2} sin (x)) - cos (2 x) = 0

化简

(\frac{3}{2} cos (x) - \frac{1}{2} sin (x)) (\frac{3}{2} cos (x) + \frac{1}{2} sin (x)) - cos (2 x) : \frac{( 3 cos ( x ) - sin ( x ) ) ( 3 cos ( x ) + sin ( x ) ) - 4 cos ( 2 x )}{4}

(\frac{3}{2} cos (x) - \frac{1}{2} sin (x)) (\frac{3}{2} cos (x) + \frac{1}{2} sin (x)) - cos (2 x)

(\frac{3}{2} cos (x) - \frac{1}{2} sin (x)) (\frac{3}{2} cos (x) + \frac{1}{2} sin (x)) = \frac{( 3 cos ( x ) - sin ( x ) ) ( 3 cos ( x ) + sin ( x ) )}{4}

(\frac{3}{2} cos (x) - \frac{1}{2} sin (x)) (\frac{3}{2} cos (x) + \frac{1}{2} sin (x))

\frac{3}{2} cos (x) = \frac{3 cos ( x )}{2}

\frac{3}{2} cos (x)

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 cos ( x )}{2}

\frac{1}{2} sin (x) = \frac{sin ( x )}{2}

\frac{1}{2} sin (x)

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot sin ( x )}{2}

乘以:

1 \cdot sin (x) = sin (x)

= \frac{sin ( x )}{2}

= (\frac{3 cos ( x )}{2} - \frac{sin ( x )}{2}) (\frac{3}{2} cos (x) + \frac{1}{2} sin (x))

\frac{3}{2} cos (x) = \frac{3 cos ( x )}{2}

\frac{3}{2} cos (x)

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 cos ( x )}{2}

\frac{1}{2} sin (x) = \frac{sin ( x )}{2}

\frac{1}{2} sin (x)

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot sin ( x )}{2}

乘以:

1 \cdot sin (x) = sin (x)

= \frac{sin ( x )}{2}

= (\frac{3 cos ( x )}{2} - \frac{sin ( x )}{2}) (\frac{3 cos ( x )}{2} + \frac{sin ( x )}{2})

化简

\frac{3 cos ( x )}{2} - \frac{sin ( x )}{2} : \frac{3 cos ( x ) - sin ( x )}{2}

\frac{3 cos ( x )}{2} - \frac{sin ( x )}{2}

使用法则

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 cos ( x ) - sin ( x )}{2}

= \frac{3 cos ( x ) - sin ( x )}{2} (\frac{3 cos ( x )}{2} + \frac{sin ( x )}{2})

合并分式

\frac{3 cos ( x )}{2} + \frac{sin ( x )}{2} : \frac{3 cos ( x ) + sin ( x )}{2}

使用法则

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 cos ( x ) + sin ( x )}{2}

= \frac{3 cos ( x ) - sin ( x )}{2} (\frac{3 cos ( x ) + sin ( x )}{2})

去除括号:

(a) = a

= \frac{3 cos ( x ) - sin ( x )}{2} \cdot \frac{3 cos ( x ) + sin ( x )}{2}

分式相乘:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( 3 cos ( x ) - sin ( x ) ) ( 3 cos ( x ) + sin ( x ) )}{2 \cdot 2}

数字相乘:

2 \cdot 2 = 4

= \frac{( 3 cos ( x ) - sin ( x ) ) ( 3 cos ( x ) + sin ( x ) )}{4}

= \frac{( 3 cos ( x ) - sin ( x ) ) ( 3 cos ( x ) + sin ( x ) )}{4} - cos (2 x)

将项转换为分式:

cos (2 x) = \frac{cos ( 2 x ) 4}{4}

= \frac{( 3 cos ( x ) - sin ( x ) ) ( 3 cos ( x ) + sin ( x ) )}{4} - \frac{cos ( 2 x ) \cdot 4}{4}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{( 3 cos ( x ) - sin ( x ) ) ( 3 cos ( x ) + sin ( x ) ) - cos ( 2 x ) \cdot 4}{4}

\frac{( 3 cos ( x ) - sin ( x ) ) ( 3 cos ( x ) + sin ( x ) ) - 4 cos ( 2 x )}{4} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

(3 cos (x) - sin (x)) (3 cos (x) + sin (x)) - 4 cos (2 x) = 0

使用三角恒等式改写

(- sin (x) + cos (x) 3) (sin (x) + cos (x) 3) - 4 cos (2 x)

使用倍角公式:

cos (2 x) = cos^{2} (x) - sin^{2} (x)

= (- sin (x) + 3 cos (x)) (sin (x) + 3 cos (x)) - 4 (cos^{2} (x) - sin^{2} (x))

化简

(- sin (x) + 3 cos (x)) (sin (x) + 3 cos (x)) - 4 (cos^{2} (x) - sin^{2} (x)) : - cos^{2} (x) + 3 sin^{2} (x)

(- sin (x) + 3 cos (x)) (sin (x) + 3 cos (x)) - 4 (cos^{2} (x) - sin^{2} (x))

乘开

(- sin (x) + 3 cos (x)) (sin (x) + 3 cos (x)) : 3 cos^{2} (x) - sin^{2} (x)

(- sin (x) + 3 cos (x)) (sin (x) + 3 cos (x))

使用平方差公式:

(a - b) (a + b) = a^{2} - b^{2}

a = 3 cos (x), b = sin (x)

= (3 cos (x))^{2} - sin^{2} (x)

(3 cos (x))^{2} = 3 cos^{2} (x)

(3 cos (x))^{2}

使用指数法则:

(a \cdot b)^{n} = a^{n} b^{n}

= (3)^{2} cos^{2} (x)

(3)^{2} : 3

使用根式运算法则:

a = a^{\frac{1}{2}}

= (3^{\frac{1}{2}})^{2}

使用指数法则:

(a^{b})^{c} = a^{b c}

= 3^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

约分:

2

= 1

= 3

= 3 cos^{2} (x)

= 3 cos^{2} (x) - sin^{2} (x)

= 3 cos^{2} (x) - sin^{2} (x) - 4 (cos^{2} (x) - sin^{2} (x))

乘开

- 4 (cos^{2} (x) - sin^{2} (x)) : - 4 cos^{2} (x) + 4 sin^{2} (x)

- 4 (cos^{2} (x) - sin^{2} (x))

使用分配律:

a (b - c) = ab - a c

a = - 4, b = cos^{2} (x), c = sin^{2} (x)

= - 4 cos^{2} (x) - (- 4) sin^{2} (x)

使用加减运算法则

- (- a) = a

= - 4 cos^{2} (x) + 4 sin^{2} (x)

= 3 cos^{2} (x) - sin^{2} (x) - 4 cos^{2} (x) + 4 sin^{2} (x)

化简

3 cos^{2} (x) - sin^{2} (x) - 4 cos^{2} (x) + 4 sin^{2} (x) : - cos^{2} (x) + 3 sin^{2} (x)

3 cos^{2} (x) - sin^{2} (x) - 4 cos^{2} (x) + 4 sin^{2} (x)

同类项相加:

3 cos^{2} (x) - 4 cos^{2} (x) = - cos^{2} (x)

= - cos^{2} (x) - sin^{2} (x) + 4 sin^{2} (x)

同类项相加:

- sin^{2} (x) + 4 sin^{2} (x) = 3 sin^{2} (x)

= - cos^{2} (x) + 3 sin^{2} (x)

= - cos^{2} (x) + 3 sin^{2} (x)

= - cos^{2} (x) + 3 sin^{2} (x)

- cos^{2} (x) + 3 sin^{2} (x) = 0

分解

- cos^{2} (x) + 3 sin^{2} (x) : (3 sin (x) + cos (x)) (3 sin (x) - cos (x))

- cos^{2} (x) + 3 sin^{2} (x)

将

3 sin^{2} (x) - cos^{2} (x)

改写为

(3 sin (x))^{2} - cos^{2} (x)

3 sin^{2} (x) - cos^{2} (x)

使用根式运算法则:

a = (a)^{2}

3 = (3)^{2}

= (3)^{2} sin^{2} (x) - cos^{2} (x)

使用指数法则:

a^{m} b^{m} = (ab)^{m}

(3)^{2} sin^{2} (x) = (3 sin (x))^{2}

= (3 sin (x))^{2} - cos^{2} (x)

= (3 sin (x))^{2} - cos^{2} (x)

使用平方差公式:

x^{2} - y^{2} = (x + y) (x - y)

(3 sin (x))^{2} - cos^{2} (x) = (3 sin (x) + cos (x)) (3 sin (x) - cos (x))

= (3 sin (x) + cos (x)) (3 sin (x) - cos (x))

(3 sin (x) + cos (x)) (3 sin (x) - cos (x)) = 0

分别求解每个部分

3 sin (x) + cos (x) = 0 or 3 sin (x) - cos (x) = 0

3 sin (x) + cos (x) = 0 : x = \frac{5 π}{6} + πn

3 sin (x) + cos (x) = 0

使用三角恒等式改写

3 sin (x) + cos (x) = 0

在两边除以

cos (x), cos (x) \neq = 0

\frac{3 sin ( x ) + cos ( x )}{cos ( x )} = \frac{0}{cos ( x )}

化简

\frac{3 sin ( x )}{cos ( x )} + 1 = 0

使用基本三角恒等式:

\frac{sin ( x )}{cos ( x )} = tan (x)

3 tan (x) + 1 = 0

3 tan (x) + 1 = 0

将

1

到右边

3 tan (x) + 1 = 0

两边减去

1

3 tan (x) + 1 - 1 = 0 - 1

化简

3 tan (x) = - 1

3 tan (x) = - 1

两边除以

3

3 tan (x) = - 1

两边除以

3

\frac{3 tan ( x )}{3} = \frac{- 1}{3}

化简

\frac{3 tan ( x )}{3} = \frac{- 1}{3}

化简

\frac{3 tan ( x )}{3} : tan (x)

\frac{3 tan ( x )}{3}

约分:

3

= tan (x)

化简

\frac{- 1}{3} : - \frac{3}{3}

\frac{- 1}{3}

使用分式法则:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{1}{3}

- \frac{1}{3}

有理化:

- \frac{3}{3}

- \frac{1}{3}

乘以共轭根式

\frac{3}{3}

= - \frac{1 \cdot 3}{3 3}

1 \cdot 3 = 3

33 = 3

33

使用根式运算法则:

a a = a

33 = 3

= 3

= - \frac{3}{3}

= - \frac{3}{3}

tan (x) = - \frac{3}{3}

tan (x) = - \frac{3}{3}

tan (x) = - \frac{3}{3}

tan (x) = - \frac{3}{3}

的通解

tan (x)

周期表（周期为

πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{5 π}{6} + πn

x = \frac{5 π}{6} + πn

3 sin (x) - cos (x) = 0 : x = \frac{π}{6} + πn

3 sin (x) - cos (x) = 0

使用三角恒等式改写

3 sin (x) - cos (x) = 0

在两边除以

cos (x), cos (x) \neq = 0

\frac{3 sin ( x ) - cos ( x )}{cos ( x )} = \frac{0}{cos ( x )}

化简

\frac{3 sin ( x )}{cos ( x )} - 1 = 0

使用基本三角恒等式:

\frac{sin ( x )}{cos ( x )} = tan (x)

3 tan (x) - 1 = 0

3 tan (x) - 1 = 0

将

1

到右边

3 tan (x) - 1 = 0

两边加上

1

3 tan (x) - 1 + 1 = 0 + 1

化简

3 tan (x) = 1

3 tan (x) = 1

两边除以

3

3 tan (x) = 1

两边除以

3

\frac{3 tan ( x )}{3} = \frac{1}{3}

化简

\frac{3 tan ( x )}{3} = \frac{1}{3}

化简

\frac{3 tan ( x )}{3} : tan (x)

\frac{3 tan ( x )}{3}

约分:

3

= tan (x)

化简

\frac{1}{3} : \frac{3}{3}

\frac{1}{3}

乘以共轭根式

\frac{3}{3}

= \frac{1 \cdot 3}{3 3}

1 \cdot 3 = 3

33 = 3

33

使用根式运算法则:

a a = a

33 = 3

= 3

= \frac{3}{3}

tan (x) = \frac{3}{3}

tan (x) = \frac{3}{3}

tan (x) = \frac{3}{3}

tan (x) = \frac{3}{3}

的通解

tan (x)

周期表（周期为

πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{π}{6} + πn

x = \frac{π}{6} + πn

合并所有解

x = \frac{5 π}{6} + πn, x = \frac{π}{6} + πn

作图

流行的例子

sin (x) = 0.731

sin (x) = 0.766

sin (x) = 0.755

3tan^2(x)-5tan(x)+2=0

3 tan^{2} (x) - 5 tan (x) + 2 = 0

solvefor θ,ρ=(4sin(φ)cos(θ))

so l v e f or θ, ρ = (4 sin (φ) cos (θ))