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人気のある三角関数 >

14.79m=((7.61_{0}^2sin(2θ_{0}))/g)

解

14.79 m = (\frac{7.6 1 _{0}^{2} sin ( 2 θ _{0} )}{g})

解

θ_{0} = \frac{arcsin ( 0.25538 \dots m g )}{2} + πn, θ_{0} = \frac{π}{2} + \frac{arcsin ( - 0.25538 \dots m g )}{2} + πn

解答ステップ

14.79 m = (\frac{7.6 1 _{0}^{2} sin ( 2 θ _{0} )}{g})

辺を交換する

\frac{7.6 1 _{0}^{2} sin ( 2 θ _{0} )}{g} = 14.79 m

以下で両辺を乗じる:

g

\frac{7.6 1 _{0}^{2} sin ( 2 θ _{0} )}{g} = 14.79 m

以下で両辺を乗じる:

g

\frac{7.6 1 _{0}^{2} sin ( 2 θ _{0} ) g}{g} = 14.79 m g; g \neq = 0

簡素化

57.9121 sin (2 θ_{0}) = 14.79 m g; g \neq = 0

57.9121 sin (2 θ_{0}) = 14.79 m g; g \neq = 0

以下で両辺を割る

57.9121; g \neq = 0

57.9121 sin (2 θ_{0}) = 14.79 m g; g \neq = 0

以下で両辺を割る

57.9121; g \neq = 0

\frac{57.9121 sin ( 2 θ _{0} )}{57.9121} = \frac{14.79 m g}{57.9121}; g \neq = 0

簡素化

sin (2 θ_{0}) = 0.25538 \dots m g; g \neq = 0

sin (2 θ_{0}) = 0.25538 \dots m g; g \neq = 0

三角関数の逆数プロパティを適用する

sin (2 θ_{0}) = 0.25538 \dots m g

以下の一般解

sin (2 θ_{0}) = 0.25538 \dots m g

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π + arcsin (a) + 2 πn

2 θ_{0} = arcsin (0.25538 \dots m g) + 2 πn, 2 θ_{0} = π + arcsin (- 0.25538 \dots m g) + 2 πn

2 θ_{0} = arcsin (0.25538 \dots m g) + 2 πn, 2 θ_{0} = π + arcsin (- 0.25538 \dots m g) + 2 πn

解く

2 θ_{0} = arcsin (0.25538 \dots m g) + 2 πn : θ_{0} = \frac{arcsin ( 0.25538 \dots m g )}{2} + πn

2 θ_{0} = arcsin (0.25538 \dots m g) + 2 πn

以下で両辺を割る

2

2 θ_{0} = arcsin (0.25538 \dots m g) + 2 πn

以下で両辺を割る

2

\frac{2 θ _{0}}{2} = \frac{arcsin ( 0.25538 \dots m g )}{2} + \frac{2 πn}{2}

簡素化

θ_{0} = \frac{arcsin ( 0.25538 \dots m g )}{2} + πn

θ_{0} = \frac{arcsin ( 0.25538 \dots m g )}{2} + πn

解く

2 θ_{0} = π + arcsin (- 0.25538 \dots m g) + 2 πn : θ_{0} = \frac{π}{2} + \frac{arcsin ( - 0.25538 \dots m g )}{2} + πn

2 θ_{0} = π + arcsin (- 0.25538 \dots m g) + 2 πn

以下で両辺を割る

2

2 θ_{0} = π + arcsin (- 0.25538 \dots m g) + 2 πn

以下で両辺を割る

2

\frac{2 θ _{0}}{2} = \frac{π}{2} + \frac{arcsin ( - 0.25538 \dots m g )}{2} + \frac{2 πn}{2}

簡素化

θ_{0} = \frac{π}{2} + \frac{arcsin ( - 0.25538 \dots m g )}{2} + πn

θ_{0} = \frac{π}{2} + \frac{arcsin ( - 0.25538 \dots m g )}{2} + πn

θ_{0} = \frac{arcsin ( 0.25538 \dots m g )}{2} + πn, θ_{0} = \frac{π}{2} + \frac{arcsin ( - 0.25538 \dots m g )}{2} + πn

グラフ

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