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人気のある三角関数 >

solvefor x,sin(x^2)+cos(y^3)=-2

解

解く

x, sin (x^{2}) + cos (y^{3}) = - 2

解

x = arcsin (- 2 - cos (y^{3})) + 2 πn, x = - arcsin (- 2 - cos (y^{3})) + 2 πn, x = π + arcsin (2 + cos (y^{3})) + 2 πn, x = - π + arcsin (2 + cos (y^{3})) + 2 πn

解答ステップ

sin (x^{2}) + cos (y^{3}) = - 2

cos (y^{3})

を右側に移動します

sin (x^{2}) + cos (y^{3}) = - 2

両辺から

cos (y^{3})

を引く

sin (x^{2}) + cos (y^{3}) - cos (y^{3}) = - 2 - cos (y^{3})

簡素化

sin (x^{2}) = - 2 - cos (y^{3})

sin (x^{2}) = - 2 - cos (y^{3})

三角関数の逆数プロパティを適用する

sin (x^{2}) = - 2 - cos (y^{3})

以下の一般解

sin (x^{2}) = - 2 - cos (y^{3})

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π + arcsin (a) + 2 πn

x^{2} = arcsin (- 2 - cos (y^{3})) + 2 πn, x^{2} = π + arcsin (2 + cos (y^{3})) + 2 πn

x^{2} = arcsin (- 2 - cos (y^{3})) + 2 πn, x^{2} = π + arcsin (2 + cos (y^{3})) + 2 πn

解く

x^{2} = arcsin (- 2 - cos (y^{3})) + 2 πn : x = arcsin (- 2 - cos (y^{3})) + 2 πn, x = - arcsin (- 2 - cos (y^{3})) + 2 πn

x^{2} = arcsin (- 2 - cos (y^{3})) + 2 πn

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

x = arcsin (- 2 - cos (y^{3})) + 2 πn, x = - arcsin (- 2 - cos (y^{3})) + 2 πn

解く

x^{2} = π + arcsin (2 + cos (y^{3})) + 2 πn : x = π + arcsin (2 + cos (y^{3})) + 2 πn, x = - π + arcsin (2 + cos (y^{3})) + 2 πn

x^{2} = π + arcsin (2 + cos (y^{3})) + 2 πn

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

x = π + arcsin (2 + cos (y^{3})) + 2 πn, x = - π + arcsin (2 + cos (y^{3})) + 2 πn

x = arcsin (- 2 - cos (y^{3})) + 2 πn, x = - arcsin (- 2 - cos (y^{3})) + 2 πn, x = π + arcsin (2 + cos (y^{3})) + 2 πn, x = - π + arcsin (2 + cos (y^{3})) + 2 πn

グラフ

人気の例

8sin(120-x)=9sin(x)

8 sin (12 0^{\circ} - x) = 9 sin (x)

cos (θ) = 0.625

solvefor x,sin(x)=3cos(x)

so l v e f or x, sin (x) = 3 cos (x)

solvefor x,1.12=0.04sin(x)

so l v e f or x, 1.12 = 0.04 sin (x)

sin (2 x) = - 0.8