tan(θ)=(5sqrt(3))/5

解答

tan (θ) = \frac{5 3}{5}

θ = \frac{π}{3} + πn

度数

θ = 6 0^{\circ} + 18 0^{\circ} n

求解步骤

tan (θ) = \frac{5 3}{5}

数字相除:

\frac{5}{5} = 1

tan (θ) = 3

tan (θ) = 3

的通解

tan (x)

周期表（周期为

πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

θ = \frac{π}{3} + πn

θ = \frac{π}{3} + πn

so l v e f or f, r = \frac{8}{sec ( f ^{0} )}

2 sin (x) - 2 = 0, 0 \leq x \leq 2 π

(2 sin (x) - 1) (sin (x) + 1) = 0

sin (A) = \frac{3}{4}

4 sin^{2} (x) + 42 cos (x) - 6 = 0