zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的三角函数 >

15*sin(45)

解答

15 \cdot sin (4 5^{\circ})

解答

\frac{15 2}{2}

+1

十进制

10.60660 \dots

求解步骤

15 sin (4 5^{\circ})

使用以下普通恒等式:

sin (4 5^{\circ}) = \frac{2}{2}

sin (4 5^{\circ})

sin (x)

周期表（周期为

36 0^{\circ} n

"）：

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{2}{2}

= 15 \cdot \frac{2}{2}

化简

15 \cdot \frac{2}{2} : \frac{15 2}{2}

15 \cdot \frac{2}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 \cdot 15}{2}

使用根式运算法则:

n a = a^{\frac{1}{n}}

2 = 2^{\frac{1}{2}}

= \frac{15 \cdot 2 ^{\frac{1}{2}}}{2}

使用指数法则:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{2 ^{\frac{1}{2}}}{2 ^{1}} = \frac{1}{2 ^{1 - \frac{1}{2}}}

= \frac{15}{2 ^{1 - \frac{1}{2}}}

数字相减:

1 - \frac{1}{2} = \frac{1}{2}

= \frac{15}{2 ^{\frac{1}{2}}}

使用根式运算法则:

a^{\frac{1}{n}} = n a

2^{\frac{1}{2}} = 2

= \frac{15}{2}

\frac{15}{2}

有理化:

\frac{15 2}{2}

\frac{15}{2}

乘以共轭根式

\frac{2}{2}

= \frac{15 2}{2 2}

22 = 2

22

使用根式运算法则:

a a = a

22 = 2

= 2

= \frac{15 2}{2}

= \frac{15 2}{2}

= \frac{15 2}{2}

流行的例子

\frac{cos ( 1 )}{2}

\frac{1}{2} cos (2 π)

tan (19 π)

(tan(42)-tan(12))/(1+tan(42)tan(12))

\frac{tan ( 4 2 ^{\circ} ) - tan ( 1 2 ^{\circ} )}{1 + tan ( 4 2 ^{\circ} ) tan ( 1 2 ^{\circ} )}

1 + sin (\frac{3 π}{2})