(1/3)^{2x+3}=5

Lösung

(\frac{1}{3})^{2 x + 3} = 5

x = - \frac{ln ( 135 )}{2 ln ( 3 )}

Dezimale

x = - 2.23248 \dots

Schritte zur Lösung

(\frac{1}{3})^{2 x + 3} = 5

Wende Exponentenregel an

(2 x + 3) ln (\frac{1}{3}) = ln (5)

Löse

(2 x + 3) ln (\frac{1}{3}) = ln (5) : x = - \frac{ln ( 135 )}{2 ln ( 3 )}

x = - \frac{ln ( 135 )}{2 ln ( 3 )}

x^{10} = e^{x}

4^{x} = \frac{8}{1 6 ^{x}}

so l v e f or x, e^{x} = 4

2^{1 - x} = 3^{x}

e^{x - 1} = 3^{\frac{2 x}{3}}