2^{1-x}=3^x

Lösung

2^{1 - x} = 3^{x}

x = \frac{ln ( 2 )}{ln ( 6 )}

Dezimale

x = 0.38685 \dots

Schritte zur Lösung

2^{1 - x} = 3^{x}

Wende Exponentenregel an

(1 - x) ln (2) = x ln (3)

Löse

(1 - x) ln (2) = x ln (3) : x = \frac{ln ( 2 )}{ln ( 6 )}

x = \frac{ln ( 2 )}{ln ( 6 )}

e^{x - 1} = 3^{\frac{2 x}{3}}

2^{(1 - x)} + 2^{(1 + x)} = 4

3^{x - 5} = 9

1 0^{x} = 18

so l v e f or x, 2 x A = B