3^29^{x-2}=27^{x+1}

Lösung

3^{2} 9^{x - 2} = 2 7^{x + 1}

x = - 5

Schritte zur Lösung

3^{2} \cdot 9^{x - 2} = 2 7^{x + 1}

Wende Exponentenregel an

2 (x - 2) + 2 = 3 (x + 1)

Löse

2 (x - 2) + 2 = 3 (x + 1) : x = - 5

x = - 5

e^{x} + e^{- x} = 8

2 - 3^{- x} = - 1

3^{x^{2} - x} = 9

2 e^{x} + 3 e^{- 3 x} = 0

2^{x} = 55