2^{x^2-1}=4^{2x+2}

Lösung

2^{x^{2} - 1} = 4^{2 x + 2}

x = 5, x = - 1

Schritte zur Lösung

2^{x^{2} - 1} = 4^{2 x + 2}

Wende Exponentenregel an

x^{2} - 1 = 2 (2 x + 2)

Löse

x^{2} - 1 = 2 (2 x + 2) : x = 5, x = - 1

x = 5, x = - 1

\frac{27}{( 3 ^{(1 - 3 x)} )} = 9

4 = 1 6^{x}

9 \cdot 3 x - 1 9 = 9^{x}

4 9^{x} = 37

4^{(2 x^{2} + x - 6)} = 1