de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Algebra >

(x^2-4)(x^2+1)(x-3)=0

Lösung

(x^{2} - 4) (x^{2} + 1) (x - 3) = 0

Lösung

x = - 2, x = 2, x = 3, x = i, x = - i

Schritte zur Lösung

(x^{2} - 4) (x^{2} + 1) (x - 3) = 0

Faktorisiere

(x^{2} - 4) (x^{2} + 1) (x - 3) : (x + 2) (x - 2) (x - 3) (x^{2} + 1)

(x + 2) (x - 2) (x - 3) (x^{2} + 1) = 0

Anwendung des Nullfaktorprinzips: Wenn

ab = 0

dann

a = 0

oder

b = 0

x + 2 = 0 or x - 2 = 0 or x - 3 = 0 or x^{2} + 1 = 0

Löse

x + 2 = 0 : x = - 2

Löse

x - 2 = 0 : x = 2

Löse

x - 3 = 0 : x = 3

Löse

x^{2} + 1 = 0 : x = i, x = - i

Die Lösungen sind

x = - 2, x = 2, x = 3, x = i, x = - i

Graph

Beliebte Beispiele

3x^3+5x^2-4x-4=0

3 x^{3} + 5 x^{2} - 4 x - 4 = 0

solvefor x,x^3y-y^2=3

so l v e f or x, x^{3} y - y^{2} = 3

x^2(x^2+4)(x^2+16)-100=0

x^{2} (x^{2} + 4) (x^{2} + 16) - 100 = 0

x^{4} - 2 x + 1 = 0

-t^3+5t^2-3t-9=0

- t^{3} + 5 t^{2} - 3 t - 9 = 0