d/(dt)(b(t)ln(t)+ct^2)

Lösung

\frac{d}{d t} (b (t) ln (t) + c t^{2})

b (ln (t) + 1) + 2 c t

Schritte zur Lösung

\frac{d}{d t} (b (t) ln (t) + c t^{2})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (b t ln (t)) + \frac{d}{d t} (c t^{2})

\frac{d}{d t} (b t ln (t)) = b (ln (t) + 1)

\frac{d}{d t} (c t^{2}) = 2 c t

= b (ln (t) + 1) + 2 c t

\int \frac{x ^{2} + 6}{x x ^{2} - 9} d x

\frac{d}{d x} (\frac{e ^{x} \cdot cos ( x )}{e ^{x} - 1})

\frac{\partial}{\partial y} ((2 x - 3 y)^{3})

x \to + (- 8) lim (2)

a re a x^{2} + x - 2, 0