f^'(x)=sqrt(x)(6+5x)

Lösung

f^{^{'}} (x) = x (6 + 5 x)

f (x) = 4 x^{\frac{3}{2}} + 2 x^{\frac{5}{2}} + c_{1}

Schritte zur Lösung

f^{'} (x) = x (6 + 5 x)

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

f (x) = \int x (6 + 5 x) d x

\int x (6 + 5 x) d x = 4 x^{\frac{3}{2}} + 2 x^{\frac{5}{2}} + c_{1}

f (x) = 4 x^{\frac{3}{2}} + 2 x^{\frac{5}{2}} + c_{1}

t an g e n t f (x) = \frac{1}{10 x}, at x = 9

\int x^{6} + \frac{1}{1 - 4 x ^{2}} d x

(i)^{^{'}}

\frac{d}{d x} (1 + tan^{2} (x))

\frac{d}{d x} (\frac{1}{( x ^{2} + y ^{2} )})