y^{''}+6y^'=0,y(0)=1,y^'(0)=1

Lösung

y^{^{''}} + 6 y^{^{'}} = 0, y (0) = 1, y^{^{'}} (0) = 1

y = 1 + \frac{1}{6} - \frac{1}{6} e^{- 6 t}

Schritte zur Lösung

y^{''} (t) + 6 y^{'} (t) = 0

Solve linear ODE:

y = 1 + \frac{1}{6} - \frac{1}{6} e^{- 6 t}

y = 1 + \frac{1}{6} - \frac{1}{6} e^{- 6 t}

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