y^'=8x^3*y^2

Lösung

y^{^{'}} = 8 x^{3} \cdot y^{2}

y = - \frac{1}{2 x ^{4} + c _{1}}

Schritte zur Lösung

y^{'} (x) = 8 x^{3} \cdot y^{2}

Solve separable ODE:

y = - \frac{1}{2 x ^{4} + c _{1}}

y = - \frac{1}{2 x ^{4} + c _{1}}

x \to 0 lim (\frac{sin ( 7 x )}{tan ( 5 x )})

y^{^{'}} + \frac{1}{x} y - e^{- x^{2}} = 0, y (1) = 0

n = 0 \sum \infty 2^{n} n^{2} x^{n}

\int ln (3) e^{x} d x

\int \frac{x ^{4} + 9}{x ^{4} + 9 x ^{2}} d x