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Beliebt Rechnen >

t^2-tyy^'+y^2=0

Lösung

t^{2} - t \cdot y \cdot y^{^{'}} + y^{2} = 0

Lösung

y = t 2 ln (t) + c_{1}, y = - t 2 ln (t) + c_{1}

Schritte zur Lösung

t^{2} - t \cdot y \cdot y^{'} (t) + y^{2} = 0

Solve Bernoulli ODE:

y = t 2 ln (t) + c_{1}, y = - t 2 ln (t) + c_{1}

y = t 2 ln (t) + c_{1}, y = - t 2 ln (t) + c_{1}

Graph

Beliebte Beispiele

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