derivative of arcsec(3x+2)

Lösung

\frac{d}{d x} (arcsec (3 x + 2))

\frac{3}{( 3 x + 2 ) 9 x ^{2} + 12 x + 3}

Schritte zur Lösung

\frac{d}{d x} (arcsec (3 x + 2))

Wende die Kettenregel an:

\frac{1}{( 3 x + 2 ) ^{2} ( 3 x + 2 ) ^{2} - 1} \frac{d}{d x} (3 x + 2)

= \frac{1}{( 3 x + 2 ) ^{2} ( 3 x + 2 ) ^{2} - 1} \frac{d}{d x} (3 x + 2)

\frac{d}{d x} (3 x + 2) = 3

= \frac{1}{( 3 x + 2 ) ^{2} ( 3 x + 2 ) ^{2} - 1} \cdot 3

Vereinfache

\frac{1}{( 3 x + 2 ) ^{2} ( 3 x + 2 ) ^{2} - 1} \cdot 3 : \frac{3}{( 3 x + 2 ) 9 x ^{2} + 12 x + 3}

= \frac{3}{( 3 x + 2 ) 9 x ^{2} + 12 x + 3}

x \to \frac{7 π}{2} - lim (sec (x))

t an g e n t f (x) = \frac{2 x}{3 - 4 x ^{3}}, at x = \frac{1}{2}

\frac{\partial}{\partial x} (\frac{2}{1 - 3 x ^{3}})

\frac{d y}{d x} = x y + 12 x

\frac{\partial}{\partial x} (\frac{x ^{2}}{2} + y^{4})