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tangent f(x)=(18)/((2x+4)^2),\at x=9

解答

切线

f (x) = \frac{18}{( 2 x + 4 ) ^{2}}, at x = 9

解答

y = - \frac{9}{1331} x + \frac{261}{2662}

求解步骤

找到切点:

(9, \frac{9}{242})

计算

f (x) = \frac{18}{( 2 x + 4 ) ^{2}}

的斜率:

\frac{df ( x )}{d x} = - \frac{9}{( x + 2 ) ^{3}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{9}{1331}

找到斜率 m=

- \frac{9}{1331}

且穿过

(9, \frac{9}{242})

的直线:

y = - \frac{9}{1331} x + \frac{261}{2662}

y = - \frac{9}{1331} x + \frac{261}{2662}

作图

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