integral from 0 to 3 of (-x^2+9)

Lösung

\int_{0}^{3} (- x^{2} + 9) d x

18

Schritte zur Lösung

\int_{0}^{3} - x^{2} + 9 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{3} x^{2} d x + \int_{0}^{3} 9 d x

\int_{0}^{3} x^{2} d x = 9

\int_{0}^{3} 9 d x = 27

= - 9 + 27

Vereinfache

= 18

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