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人気のある微分積分 >

integral from 0 to 1 of t13^{t^2}

解

\int_{0}^{1} t 1 3^{t^{2}} d t

解

\frac{6}{ln ( 13 )}

+1

十進法表記

2.33922 \dots

解答ステップ

\int_{0}^{1} t \cdot 1 3^{t^{2}} d t

u置換積分法を適用する

= \int_{1}^{13} \frac{1}{2 ln ( 13 )} d u

定数の積分:

\int a d x = a x

= [\frac{1}{2 ln ( 13 )} u]_{1}^{13}

限度を計算する:

\frac{6}{ln ( 13 )}

= \frac{6}{ln ( 13 )}

グラフ

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