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Beliebt Rechnen >

integral of 6(x^2+1)(x^3+3x)^3

Lösung

\int 6 (x^{2} + 1) (x^{3} + 3 x)^{3} d x

Lösung

6 (\frac{x ^{12}}{12} + x^{10} + \frac{9 x ^{8}}{2} + 9 x^{6} + \frac{27 x ^{4}}{4}) + C

Schritte zur Lösung

\int 6 (x^{2} + 1) (x^{3} + 3 x)^{3} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int (x^{2} + 1) (x^{3} + 3 x)^{3} d x

Multipliziere aus

(x^{2} + 1) (x^{3} + 3 x)^{3} : x^{11} + 10 x^{9} + 36 x^{7} + 54 x^{5} + 27 x^{3}

= 6 \cdot \int x^{11} + 10 x^{9} + 36 x^{7} + 54 x^{5} + 27 x^{3} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 6 (\int x^{11} d x + \int 10 x^{9} d x + \int 36 x^{7} d x + \int 54 x^{5} d x + \int 27 x^{3} d x)

\int x^{11} d x = \frac{x ^{12}}{12}

\int 10 x^{9} d x = x^{10}

\int 36 x^{7} d x = \frac{9 x ^{8}}{2}

\int 54 x^{5} d x = 9 x^{6}

\int 27 x^{3} d x = \frac{27 x ^{4}}{4}

= 6 (\frac{x ^{12}}{12} + x^{10} + \frac{9 x ^{8}}{2} + 9 x^{6} + \frac{27 x ^{4}}{4})

Füge eine Konstante zur Lösung hinzu

= 6 (\frac{x ^{12}}{12} + x^{10} + \frac{9 x ^{8}}{2} + 9 x^{6} + \frac{27 x ^{4}}{4}) + C

Graph

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