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人気のある微分積分 >

integral from-1 to 1 of (6x^2-2x+1)

解

\int_{- 1}^{1} (6 x^{2} - 2 x + 1) d x

解

6

解答ステップ

\int_{- 1}^{1} 6 x^{2} - 2 x + 1 d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 6 x^{2} d x - \int_{- 1}^{1} 2 x d x + \int_{- 1}^{1} 1 d x

\int_{- 1}^{1} 6 x^{2} d x = 4

\int_{- 1}^{1} 2 x d x = 0

\int_{- 1}^{1} 1 d x = 2

= 4 - 0 + 2

簡素化

= 6

グラフ

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