sum from n=1 to infinity of 1/((n)(n+1))

Lösung

n = 1 \sum \infty \frac{1}{( n ) ( n + 1 )}

1

Schritte zur Lösung

n = 1 \sum \infty \frac{1}{n ( n + 1 )}

Teleskopreihen-Test anwenden:

1

= 1

n = 1 \sum \infty 9 n^{2} e^{- n^{3}}

n = 0 \sum \infty (1 + \frac{1}{2 n})^{n}

n = 1 \sum \infty ln (\frac{3 n + 1}{n})

n = 1 \sum \infty \frac{3}{( n ( n + 3 ) )}

k = 1 \sum \infty \frac{9}{k ( k + 2 )}