y^'=-10x^2y

Lösung

y^{^{'}} = - 10 x^{2} y

y = e^{- \frac{10 x ^{3}}{3} + c_{1}}

Schritte zur Lösung

y^{'} (x) = - 10 x^{2} y

Solve separable ODE:

y = e^{- \frac{10 x ^{3}}{3} + c_{1}}

y = e^{- \frac{10 x ^{3}}{3} + c_{1}}

x^{3} y^{^{'}} + (5 x^{2} - 8) y = 0

3 y^{^{'}} - y = 0

y^{^{'}} + cos (t) y = cos (t)

\frac{d y}{d x} = \frac{x}{2 y x + y}

y^{^{'}} = \frac{2 x + x y ^{2}}{4 y + x ^{2} y}