laplacetransform-5e^{2t}

Lösung

laplace transformation

- 5 e^{2 t}

- \frac{5}{s - 2}

Schritte zur Lösung

L {- 5 e^{2 t}}

Verwende die konstante Multiplikationseigenschaft der Laplace-Transformation:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 5 L {e^{2 t}}

L {e^{2 t}} : \frac{1}{s - 2}

= - 5 \cdot \frac{1}{s - 2}

Fasse

- 5 \frac{1}{s - 2}

zusammen:

- \frac{5}{s - 2}

= - \frac{5}{s - 2}

n = 1 \sum \infty n! (x - 1)^{n}

\int_{1}^{4} x^{2} - 3 x d x

\int_{0}^{4} \frac{x}{x ^{2} - 1} d x

\frac{\partial}{\partial x} (3 x + 2 y - 3)

a re a y = x^{2}, y = 3 - x, (0, 1.3)