y^'=(y^4-3)/((4xy^3))

Lösung

y^{^{'}} = \frac{y ^{4} - 3}{( 4 x y ^{3} )}

y = 4 c_{1} x + 3, y = - 4 c_{1} x + 3

Schritte zur Lösung

y^{'} (x) = \frac{y ^{4} - 3}{( 4 x y ^{3} )}

Solve separable ODE:

y = 4 c_{1} x + 3, y = - 4 c_{1} x + 3

y = 4 c_{1} x + 3, y = - 4 c_{1} x + 3

x \to - 1 lim (4 x^{2} - 3 x + 2)

\int \frac{1}{x ^{4} x ^{2} - 1} d x

\frac{\partial}{\partial x} (e^{x} sin (x + y))

d er i v a t i v e \frac{8}{x x ^{2} - 4}

x \to \infty lim ((k)^{x})